Zapisz w zeszycie temat lekcji.
Temat: Pole koła. data 03.06.2020
Pole koła obliczamy ze wzoru:
P = ∏∙r2, gdzie r to promień koła.
Zapisz polecenia i rozwiązania zadań od 1 do 5.
1) Zad. 1 Oblicz pole koła o promieniu:
a) r = 3 P = ∏∙r2 = ∏∙
32 = ∏∙9 = 9 ∏
b) r = 6 P = ∏∙r2 = ∏∙62 = ∏∙36 = 36 ∏
c) r = 10 P = ∏∙r2 = ∏∙102 = ∏∙100 = 100 ∏
d) r = 1 P = ∏∙r2 = ∏∙12 = ∏∙1 = 1 ∏
2) Zad. 2 Oblicz pole koła o średnicy:
a) d = 6 wtedy r = 3 P = ∏∙r2 = ∏∙32 = ∏∙9 = 9 ∏
b) d = 12 wtedy r = 6 P = ∏∙r2 = ∏∙62 = ∏∙36 = 36 ∏
c) d = 20 wtedy r = 10 P = ∏∙r2 = ∏∙102 = ∏∙100 = 100 ∏
d) d = 2 wtedy r = 1 P = ∏∙r2 = ∏∙12 = ∏∙1 = 1 ∏
3) Zad. 3 Oblicz średnicę i promień koła o polu:
a) P = 16 ∏ = ∏∙r2
zatem r2 = 16, a r = 4, d = 8
b) P = 25 ∏ = ∏∙r2
zatem r2 = 25, a r = 5, d = 10
c) P = 81 ∏ = ∏∙r2
zatem r2 = 81, a r = 9, d = 18
d) P = 100 ∏ = ∏∙r2
zatem r2 = 100, a r = 10, d = 20
4) Zad. 4 Oblicz pole koła o obwodzie 16 ∏ .
L = 16 ∏ = ∏∙d zatem d= 16, r = 8
P = ∏∙r2 = ∏∙82 = ∏∙64 = 64 ∏
5) Oblicz obwód koła o polu 16 ∏ .
P = 16 ∏ = ∏∙r2 zatem r2 = 16, a r = 4, d= 8
L = ∏∙d = ∏∙8 = 8∏
Komentarze
Prześlij komentarz